1972 Ap Chemistry Free Response Answers Repack -

After the reaction, 0.176 mol of NO reacts with 0.088 mol of O₂ to produce 0.176 mol of NO₂, leaving 0.088 mol of O₂ unreacted. The total number of moles after the reaction is 0.264 mol. Using the ideal gas law: P = (0.264 mol × 0.0821 L·atm/mol·K × 298 K) / 5.00 L ≈ 1.29 atm.

A rigid 5.00 L cylinder contains 24.5 g of N₂(g) and 28.0 g of O₂(g). Calculate the total pressure, in atm, of the gas mixture in the cylinder at 298 K.

Detailed solutions and scoring guides for similar legacy problems can be found on resources like Scribd or Coach Coker's Chemistry .

: You can find detailed keys for the Gas Law problems and Acid-Base solutions through various teacher-uploaded repositories. AP FRQ WORKED ANSWER ARCHIVE 1972 ap chemistry free response answers

Given the following thermochemical equations at 25°C:

A voltaic cell is constructed with a Zn/Zn²⁺ (0.10 M) half-cell and a Cu/Cu²⁺ (0.0010 M) half-cell. Standard reduction potentials: Zn²⁺ + 2e⁻ → Zn (E° = -0.76 V); Cu²⁺ + 2e⁻ → Cu (E° = +0.34 V). Calculate the cell potential (E_cell) at 25°C.

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"A 0.500 gram sample of a pure metal, X, reacts completely with excess hydrochloric acid to produce 280. mL of hydrogen gas collected over water at 25.0°C and a total pressure of 740. mm Hg. The vapor pressure of water at 25.0°C is 23.8 mm Hg. Determine the equivalent weight of the metal."

Below are key solutions and concepts for specific questions from that year: Acid-Base & Stoichiometry (Question 1) This problem involved a 5.00-gram mixture of KOHcap K cap O cap H K2CO3cap K sub 2 cap C cap O sub 3 KClcap K cap C l reacting with HClcap H cap C l : You must determine the percentage of K2CO3cap K sub 2 cap C cap O sub 3 by calculating the moles of CO2cap C cap O sub 2 gas produced ( ). Using the stoichiometry of

A solution contains Ag⁺, Pb²⁺, and Zn²⁺. Describe a procedure to separate and confirm each ion using 1M HCl, 1M H2SO4, and 1M NH3(aq). Write net ionic equations. After the reaction, 0

) for a redox reaction. A specific example from this year resulted in a cap delta cap G raised to the composed with power cap delta cap H raised to the composed with power Coordination Chemistry

n=(740/760 atm)(0.249 L)(0.08206 L⋅atm/mol⋅K)(295 K)≈0.0100 mol CO2n equals the fraction with numerator open paren 740 / 760 atm close paren open paren 0.249 L close paren and denominator open paren 0.08206 L center dot atm/mol center dot K close paren open paren 295 K close paren end-fraction is approximately equal to 0.0100 mol cap C cap O sub 2 Since 1 mole of K2CO3cap K sub 2 cap C cap O sub 3 produces 1 mole of CO2cap C cap O sub 2 , there is 0.0100 mol of K2CO3cap K sub 2 cap C cap O sub 3 . Mass of . . Part (b): The excess HClcap H cap C l is titrated with 86.6 mL of 1.50 M NaOHcap N a cap O cap H . Calculate the percentages of KOHcap K cap O cap H and KClcap K cap C l . Solution: Total moles . Moles HClcap H cap C l used by . Excess HClcap H cap C l (from titration) . Moles HClcap H cap C l reacted with . Mass ( 56.2%56.2 % ). Mass ( 16.2%16.2 % ). 2. Acid-Base Buffers Given a solution of ammonium chloride ( NH4Clcap N cap H sub 4 cap C l ), what is needed to prepare a buffer? Answer: You need a weak base, such as ammonia ( NH3cap N cap H sub 3 ). Mechanism: Adding Strong Acid ( H+cap H raised to the positive power ): The base ( NH3cap N cap H sub 3 ) reacts with it:

To find the original prompts:

The 1972 exam featured 18 free-response questions, a number that remained consistent from 1971 through 1975. These questions were designed to test a student's ability to solve complex quantitative problems, write net ionic equations, and provide thoughtful explanations for conceptual scenarios. The exam covered a broad range of topics, including stoichiometry, gas laws, thermodynamics, and chemical equilibrium.