Fixed Fixed - Sqlite3 Tutorial Query Python

print("\n--- Users with their posts ---") for row in get_users_with_posts(): username, email, title, content = row print(f"User: username (email)") if title: print(f" Post: title - content[:50]...") else: print(" No posts yet")

Use fetchall() to retrieve all matching rows as a list of tuples.

.exit

conn.commit() conn.close()

| ❌ | ✅ Fixed | Why | |-------------|-------------|---------| | f"SELECT * FROM users WHERE name = 'name'" | "SELECT * FROM users WHERE name = ?", (name,) | Prevents SQL injection | | cursor.execute(query) (no try-except) | try: cursor.execute(query) except sqlite3.Error: | Handles errors gracefully | | Manual conn.commit() | Use context manager | Auto-commit or rollback | | cursor.fetchall() on large datasets | cursor.fetchmany(100) in loop | Memory efficient | sqlite3 tutorial query python fixed

conn.commit() conn.close()

By following this , you’ve learned how to: print("\n--- Users with their posts ---") for row

# 5. Query Data print("\n--- Query Results ---")

# Method 1: Using parameterized queries (SECURE - prevents SQL injection) def insert_user(username, email, age): cursor.execute(''' INSERT INTO users (username, email, age) VALUES (?, ?, ?) ''', (username, email, age)) conn.commit() return cursor.lastrowid age): cursor.execute(''' INSERT INTO users (username

except sqlite3.Error as e: print(f"Error adding employee: e")